Group By的用法示例

    技术2022-05-11  70

     

    CREATE   TABLE  #A(    UserId         INT ,    UserName     NVARCHAR ( 50 ),    Mobile         VARCHAR ( 20 )) INSERT   INTO  #A  VALUES ( 1 , ' aaa ' , ' 13926436455 ' ) INSERT   INTO  #A  VALUES ( 3 , ' bbb ' , ' 13587656455 ' ) CREATE   TABLE  #C(    UserId         INT ,    Mobile         VARCHAR ( 20 ),    PostTime     DATETIME ,    HasTime         INT ) INSERT   INTO  #C  VALUES ( 1 , ' 13345656455 ' , ' 2007-09-28 17:40:46.310 ' , ' 51 ' ) INSERT   INTO  #C  VALUES ( 1 , ' 13345656455 ' , ' 2007-09-28 17:40:50.937 ' , ' 11 ' ) INSERT   INTO  #C  VALUES ( 2 , ' 13545656455 ' , ' 2007-09-28 17:41:06.187 ' , ' 13 ' ) INSERT   INTO  #C  VALUES ( 3 , ' 13587656455 ' , ' 2007-09-28 17:41:21.230 ' , ' 13 ' ) INSERT   INTO  #C  VALUES ( 4 , ' 13987656455 ' , ' 2007-09-28 17:41:33.640 ' , ' 34 ' ) INSERT   INTO  #C  VALUES ( 4 , ' 13987656455 ' , ' 2007-09-28 17:41:40.810 ' , ' 14 ' ) INSERT   INTO  #C  VALUES ( 1 , ' 13345656455 ' , ' 2007-09-28 17:41:59.450 ' , ' 19 ' ) -- 和#A表连接获取UserName,根据#C表各Mobile和#A表各UserName的HasTime的和,按时间和降序排列 -- 连接后表中UserName为NULL的将其默认设置为“匿名用户” SELECT  #C.Mobile, ISNULL (UserName, ' 匿名用户 ' AS  UserName, SUM (HasTime)  AS  SumTime  FROM  #C  LEFT   JOIN  #A  ON  #C.UserId = #A.UserId  GROUP   BY  #C.Mobile,#A.UserName  ORDER   BY  SumTime  DESC

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