提出纯脚本的HoverMenuBehavior及冒泡提示框

    技术2022-05-11  65

    1、引用相关JS文件    <script src="MicrosoftAjax.debug.js" type="text/javascript"></script>    <script src="AjaxControlToolkit.Common.Common.js" type="text/javascript"></script>    <script src="AjaxControlToolkit.ExtenderBase.BaseScripts.js" type="text/javascript"></script>    <script src="AjaxControlToolkit.PopupExtender.PopupBehavior.js" type="text/javascript"></script>    <script src="AjaxControlToolkit.HoverExtender.HoverBehavior.js" type="text/javascript"></script>    <script src="AjaxControlToolkit.HoverMenu.HoverMenuBehavior.js" type="text/javascript"></script>

    2、放置一个作为触发源的html元素<input type="submit" name="btnRightShow" value="向右显示" id="btnRightShow" />

    3、放置一个触发事件后动态显示的元素<div id="tipRightPanel" class="tipRightPanel" style="width:80px;"></div>

    4、在页面的尾部添加初始化脚本    <script type="text/javascript">    <!--        Sys.Application.initialize();        Sys.Application.add_init(function() {            $create(AjaxControlToolkit.HoverMenuBehavior, {                //"HoverCssClass":"popupHover",                "OffsetY":-20,                "PopDelay":50,                "PopupPosition":4,                "dynamicServicePath":"tipRight.htm",                "id":"hme1",                "popupElement":$get("tipRightPanel")                },                 null, null, $get("btnRightShow"));        });    // -->        </script> 


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