如何识别无BOM的UTF8文本

    技术2022-05-11  83

    /* IsTextUTF8 * * UTF-8 is the encoding of Unicode based on Internet Society RFC2279 * ( See http://www.cis.ohio-state.edu/htbin/rfc/rfc2279.html ) * * Basicly: * 0000 0000-0000 007F - 0xxxxxxx  (ascii converts to 1 octet!) * 0000 0080-0000 07FF - 110xxxxx 10xxxxxx    ( 2 octet format) * 0000 0800-0000 FFFF - 1110xxxx 10xxxxxx 10xxxxxx (3 octet format) * (this keeps going for 32 bit unicode)  *  * * Return value:  TRUE, if the text is in UTF-8 format. *                FALSE, if the text is not in UTF-8 format. *                We will also return FALSE is it is only 7-bit ascii, so the right code page *                will be used. * *                Actually for 7 bit ascii, it doesn't matter which code page we use, but *                notepad will remember that it is utf-8 and "save" or "save as" will store *                the file with a UTF-8 BOM.  Not cool. */

    INT IsTextUTF8( LPSTR lpstrInputStream, INT iLen ){    INT   i;    DWORD cOctets;  // octets to go in this UTF-8 encoded character    UCHAR chr;    BOOL  bAllAscii= TRUE;

        cOctets= 0;    for( i=0; i < iLen; i++ ) {        chr= *(lpstrInputStream+i);

            if( (chr&0x80) != 0 ) bAllAscii= FALSE;

            if( cOctets == 0 )  {            //            // 7 bit ascii after 7 bit ascii is just fine.  Handle start of encoding case.            //            if( chr >= 0x80 ) {                 //               // count of the leading 1 bits is the number of characters encoded               //               do {                  chr <<= 1;                  cOctets++;               }               while( (chr&0x80) != 0 );

                   cOctets--;                        // count includes this character               if( cOctets == 0 ) return FALSE;  // must start with 11xxxxxx            }        }        else {            // non-leading bytes must start as 10xxxxxx            if( (chr&0xC0) != 0x80 ) {                return FALSE;            }            cOctets--;                           // processed another octet in encoding        }    }

        //    // End of text.  Check for consistency.    //

        if( cOctets > 0 ) {   // anything left over at the end is an error        return FALSE;    }

        if( bAllAscii ) {     // Not utf-8 if all ascii.  Forces caller to use code pages for conversion        return FALSE;    }

        return TRUE;}

     

    不过这段代码是有bug的,微软记事本很著名的“联通”的bug也是这段代码引起的,暂时还没找到更好的识别无BOM的UTF8文本的更好的办法 


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