Spring+Hibernate3的框架中用到了关联查询
表User：Address是一对多的关系
UserBean中有一个addresses的Set
现在要查询出这样的User，拥有Address中门牌doorplate为"642"的User，
现在DB中只有一个这样的User，这个User拥有门牌doorplate为"642"的Address五个~~
创建DetachedCriteria 的语句如下：
DetachedCriteria detachedCriteria = DetachedCriteria.forClass(User.
class);
detachedCriteria.createCriteria(
"addresses"
).add(Restrictions.like(
"doorplate"
,
"642"
));实际查询语句如下： List list = getHibernateTemplate().findByCriteria(queryCriteria); 理论上查询出来的list应该User的list是1总结如下1：DetachedCriteria addressCriteria = DetachedCriteria.forClass(User.class).createCriteria("addresses");addressCriteria.add(Restrictions.eq("doorplate","642")):2：DetachedCriteria addressCriteria = DetachedCriteria.forClass(User.class).createAlias("addresses", "a");addressCriteria.add(Restrictions.eq("a.doorplate","642")):
