PLSQL 综合复习题之答案(1)

    技术2022-05-11  62

    PL/SQL 综合复习题之答案(1)

     一

               --1            select b.produce,sum(a.num) from commod1 a,commod2 b                   where a.id=b.idd group by b.produce;                        --2            select sum(num) from commod1 where num between 10 and 20;            --3            select sort,max(price) from commod1 group by sort;            --4            select s.stu_name from s_student s,x_course x                             where x.stu_id=s.stu_id                                   and x.cour_id in (select x.cour_id                                                from x_course x,s_student s                                               where x.stu_id=s.stu_id                                                and stu_name='@ml');             --5               select nvl(score,-1) from x_course;

    --1            select a.sname from s a,sc b where a.sno=b.sno and                          b.cno <>(select cno                                      from c                                      where cteacher='李明');                                       --2            select a.sname,avg(b.scgrade) from s a,sc b                          where a.sno=b.sno                              and b.scgrade in (select scgrade                                                 from sc where scgrade<60)                                                  group by a.sname;                                          --3           方法1:           /  *select a.sname from s a,( select a.sno                            from sc a,sc b                             where a.sno=b.sno and a.cno='01'                                and b.cno='02')aa            where a.sno in aa.sno ;*/                     方法2:            /*  select a.sname            from s a, sc b            where a.sno = b.sno and b.cno='01'            intersect             select a.sname            from s a, sc b            where a.sno = b.sno and b.cno='02';*/                      方法3:          /*select c.sname         from (select sno from sc where cno = '01')a,         ( select sno from sc where cno = '02')b, s c         where a.sno = b.sno and a.sno = c.sno and b.sno = c.sno;         */

            --4       /*select c.sno,c.sname from (select scgrade,sno from sc where cno='01')a,                     (select scgrade from sc where sno='2' and cno='01')b, s c                     where c.sno= a.sno and a.scgrade>b.scgrade;*/      --5      /*select c.sno,a.scgrade,b.scgrade from (select scgrade,sno from sc where cno='01')a,                 (select scgrade,sno from sc where cno='02')b, s c                where c.sno=a.sno and c.sno=b.sno and a.scgrade>b.scgrade;*/ 

          --1      /* select deptno,avg(sal) from emp where sal>=600 group by deptno;*/       --2      /* select e.empno,d.dname from emp e,dept d                                where e.deptno=d.deptno and e.empno='001';*/       --3      /* update emp set sal=sal*0.1+sal where deptno=30 and sal<2000;*/  


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