(hdu1098)Ignatius's puzzle

    技术2022-05-18  15

    Problem Description Ignatius is poor at math,he falls across a puzzle problem,so he has no choice but to appeal to Eddy. this problem describes that:f(x)=5*x^13+13*x^5+k*a*x,input a nonegative integer k(k<10000),to find the minimal nonegative integer a,make the arbitrary integer x ,65|f(x)if no exists that a,then print "no".  

     

    Input The input contains several test cases. Each test case consists of a nonegative integer k, More details in the Sample Input.  

     

    Output The output contains a string "no",if you can't find a,or you should output a line contains the a.More details in the Sample Output.  

     

    Sample Input 11 100 9999  

     

    Sample Output 22 no 43  

    题意:给定k,求最小的a满足f(x)=5*x^13+13*x^5+k*a*x,如果不存在就输出no

    a满足f(x)则a满足f(x+1) ->  65|18 + ka ->  ka = 47(mod 65) 有解的情况 gcd(k,65)|47  -> gcd(k,65) == 1的时候有解

    暴力求解;

    #include <stdio.h> #include <string.h> int gcd(int a,int b) { return b ? gcd(b,a % b) : a; } int main() { int k; while(scanf("%d",&k)!=EOF) { if(gcd(k,65) == 1) { int i; for(i = 0; ;i++) { if(k * i % 65 == 47) { printf("%d/n",i); break; } } } else printf("no/n"); } return 0; }


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