C#.net 获取XML文件中某个时间标签判断

C#代码

 

导入命名空间

using System.Xml;

 

 

    /// <summary>    /// 获取xml文件中的标签值做判断    /// </summary>    protected void GetXmlFile()    {        XmlDocument doc = new XmlDocument();        doc.Load("D://MyXML.xml");        XmlNodeList nodelist = doc.SelectNodes("root/Action");        int nodelistcount = nodelist.Count;        int count = 0;//判断xml中不相等的数量        string src = "";//获取与当前年份不相同的数据        for (int i = 0; i < nodelistcount; i++)        {            if (DateTime.Now.ToString("yyyy-MM-dd") == nodelist.Item(i).SelectNodes("day").Item(0).InnerText)            {                src += nodelist.Item(i).SelectNodes("day").Item(0).InnerText + " 与当前年份相等!<br/>";            }            else            {                src += nodelist.Item(i).SelectNodes("day").Item(0).InnerText + "，";                count++;            }        }        src += count + " 个不与当前年份相等";    }

 

 

 

XML文件

<?xml version="1.0" encoding="utf-8" ?>

<root><Action>  <day name="day">2011-03-07</day></Action>

<Action>  <day name="day">2011-03-08</day></Action>

<Action>  <day name="day">2011-03-09</day></Action>

<Action>  <day name="day">2011-03-10</day></Action>

<Action>  <day name="day">2011-03-11</day></Action></root>