Problem 2581 Bomb the Bridge

    技术2022-05-20  46

    Problem 2581 Bomb the Bridge

     

     

    Problem Description

    You want to destroy a bridge with bombs .The lower-left corner of the bridge is at (0,0) and upper-right corner is at ( w , l ). There are already b bombs exploded , the i-th bombcreated a hole of radius ri centering at (xi , yi) .You want to throw exactly one more bomb so that the bridge is split into two connected parts( though the two parts can share a finite number of points),so that no one can go through the bridge from y=0 to y=l .You task is to find the minimal radius of the last bomb to split the bridge , assuming that the last bomb can explode precisely at the position you want (possibly at non-integer 

    coordinates).Note that you are only allowed to use bombs with integer radius .That is ,even if a bomb with radius 1.01 is sufficient , you have to use a bomb with radius 2, since you only have bombs with integer radius.

     

     

    Input

    The first line contains t (1<= t <=10), the number of test cases followed . Each test case begins with three integers w , l, b (1<= w , l<=100 , 0<= b <= 10). Each of the following b lines contains three integers integers xi, yi , ri (0<= x <=w, 0<= y <=l, 0< r <=100). The bridge is guaranteed to be connected before the last bomb.

     

     

    Output

    For each test case , print the minimal radius of the last bomb.

     

     

    Sample Input

    3

    100 100 2

    15 50 20

    90 50 30 

    100 100 1

    50 50 40

    100 100 1

    10 50 10

     

     

    Sample Output

    13 

    50 

    40

     

    此题很水

    四种情况

    1,上下桥面都没被炸开口

     

    此种情况 炸弹最小半径为桥宽

     

    2,只有上桥面被炸开口

     

    将与上桥面开口圆有交点的圆视为一个整体,找出这个整体最下面的点,向下桥面作垂线即为直径

     

    3,只有下桥面被炸开口

     

    做法同2

     

    4,上下桥面都被炸开

     

    将与上桥面开口圆有交点的圆视为一个整体a;将与下桥面开口圆有交点的圆视为一个整体b

    分别从a,b中任取一圆记下两圆圆心距减去半径和(最小相切圆直径)Ci  最后记下c = min(C1,C2,C3,。。。)

    找出整体a最下面的点,向下桥面作垂线记为d

    找出整体b最上面的点,向上桥面作垂线记为e

    结果即为min(c,d,e)

     

     

     


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