http://apps.hi.baidu.com/share/detail/2538028
Hibernate多表查询实践总结（2006-11-24）
实在无聊，前段时间做了个对单表的ZCGC(增删改查)，练了练手，虽然做过，但还是碰到了不少问题，让自己对struts+hibernate模式开发更加熟练了点。今天，我做多表的复习的时候，又碰到问题了，现在将关键点记录下来，以免日后再有相同问题出现，以便查阅。
我做的两张表：一张department表，一张employee表，建表语句如下：
drop table employee
create table EMPLOYEE
(
ID NUMBER(10) not null,
parentID number(10),
NAME VARCHAR2(20),
AGE NUMBER(3),
PASSWARD VARCHAR2(12),
CSRQ DATE,
PICTURE varchar(12),
primary key(id),
foreign key(parentID) references department(id)
)
drop table department
create table department
(
id number(10) not null,
dep_id varchar2(20),
dep_mc varchar2(20),
primary key(id)
)
其中，employee表中的parentID是department表的外键，department和employee表是一对多的关系，反过来是多对一的关系。怎么叫都可以。
Department.hbm.xml代码如下：
<hibernate-mapping>
<class name="com.dudeng.employee.hibernate.vo.Department"
table="DEPARTMENT" schema="DUDENG">
<id name="id" type="java.lang.Long">
<column name="ID" precision="10" scale="0" />
<generator class="sequence">
<param name="sequence">seq_department</param>
</generator>
</id>
<property name="dep_id" type="java.lang.String">
<column name="DEP_ID" length="20" not-null="false" />
</property>
<property name="dep_mc" type="java.lang.String">
<column name="DEP_MC" length="20" not-null="false" />
</property>
<set name="employees" inverse="true">
<key>
<column name="parentID" precision="5" scale="0"
not-null="true" />
</key>
<one-to-many
class="com.dudeng.employee.hibernate.vo.Employee" />
</set>
</class>
</hibernate-mapping>
Employee.hbm.xml的代码如下：
<hibernate-mapping>
<class name="com.dudeng.employee.hibernate.vo.Employee"
table="EMPLOYEE" schema="DUDENG">
<id name="id" type="java.lang.Long">
<column name="ID" precision="10" scale="0" />
<generator class="sequence">
<param name="sequence">seq_employee</param>
</generator>
</id>
<many-to-one name="department" class="com.dudeng.employee.hibernate.vo.Department">
<column name="parentID" precision="5" scale="0" not-null="true" />
</many-to-one>
<property name="name" type="java.lang.String">
<column name="NAME" length="20" not-null="false" />
</property>
<property name="age" type="java.lang.Long">
<column name="AGE" precision="3" scale="0" not-null="false" />
</property>
<property name="passward" type="java.lang.String">
<column name="PASSWARD" length="12" not-null="false" />
</property>
<property name="csrq" type="java.util.Date">
<column name="CSRQ" length="7" not-null="false" />
</property>
<property name="picture" type="java.lang.String">
<column name="PICTURE" length="20" not-null="false"/>
</property>
</class>
</hibernate-mapping>
查询结果集合：
List list = null;
String QueryStr = "from Employee emp,Department dep where emp.department = dep.id";
EmployeeBiz empbiz = EmployeeBiz.getInstance();
list = empbiz.find(QueryStr);
for (int i = 0; i < list.size(); i++)
{
Object[] obj = (Object[]) list.get(i);
for (int j = 0; j < obj.length; j++)
{
if (obj[j] instanceof Employee)
{
Employee emp = (Employee) obj[j];
System.out.print(emp.getName());
}
elseif (obj[j] instanceof Department)
{
Department dep = (Department) obj[j];
System.out.print(dep.getDep_mc());
}
}
System.out.println();
}
以上特别注意的地方：emp.department不能写成emp.parentID，我上网查了半天才找出原因的。开始写成emp.parentID了，后来改成emp.department程序运行正常了。
另外种方法 写个DocumentDetail对象，然后获得查询结果集合 select new com.cetc.bean.util.vo.DocumentDetail(da.contentid,dd.id,dd.filename,dd.filesource,dd.filesize,dd.mimetype,dd.author,dd.filepath) from DocumentDetail dd,ContentAttachment da where dd.id=da.documentid 构造函数一定要写好 public DocumentDetail(String contentid,String documentid,String fileName,String fileSource,Long fileSize,String mimeType,String author,String filePath){ this.contentid = contentid; this.documentid = documentid; this.fileName = fileName; this.fileSource = fileSource; this.fileSize = fileSize; this.mimeType = mimeType; this.author = author; this.filePath = filePath; }
最后 视图！！！ 哈哈哈
