OpenCV中获取图像某一像素值

    技术2022-05-20  35

    This is a basic example for the OpenCV.

    First we must know the structure of IplImage:

    IPL image: IplImage |-- int nChannels; // Number of color channels (1,2,3,4) |-- int depth; // Pixel depth in bits: | // IPL_DEPTH_8U, IPL_DEPTH_8S, | // IPL_DEPTH_16U,IPL_DEPTH_16S, | // IPL_DEPTH_32S,IPL_DEPTH_32F, | // IPL_DEPTH_64F |-- int width; // image width in pixels |-- int height; // image height in pixels |-- char* imageData; // pointer to aligned image data | // Note that color images are stored in BGR order |-- int dataOrder; // 0 - interleaved color channels, | // 1 - separate color channels | // cvCreateImage can only create interleaved images |-- int origin; // 0 - top-left origin, | // 1 - bottom-left origin (Windows bitmaps style) |-- int widthStep; // size of aligned image row in bytes |-- int imageSize; // image data size in bytes = height*widthStep |-- struct _IplROI *roi;// image ROI. when not NULL specifies image | // region to be processed. |-- char *imageDataOrigin; // pointer to the unaligned origin of image data | // (needed for correct image deallocation) | |-- int align; // Alignment of image rows: 4 or 8 byte alignment | // OpenCV ignores this and uses widthStep instead |-- char colorModel[4]; // Color model - ignored by OpenCV //------------------------------------------------------------------------------ int  main( int  argc,  char *  argv[]) {     IplImage *img=cvLoadImage("c://fruitfs.bmp",1);    CvScalar s;    for(int i=0;i<img->height;i++){        for(int j=0;j<img->width;j++){        s=cvGet2D(img,i,j); // get the (i,j) pixel value        printf("B=%f, G=%f, R=%f ",s.val[0],s.val[1],s.val[2]);        s.val[0]=111;        s.val[1]=111;        s.val[2]=111;        cvSet2D(img,i,j,s);//set the (i,j) pixel value        }    }    cvNamedWindow("Image",1);     cvShowImage("Image",img);    cvWaitKey(0); //等待按键     cvDestroyWindow( "Image" );//销毁窗口    cvReleaseImage( &img ); //释放图像     return 0;}     其实还有更好的方法,例如将其封装成类,调用起来更加方便,效率也很高。


    最新回复(0)