c# 事物处理

    技术2022-05-20  41

    对两个数据表同时进行insert操作处理,对它们的插入操作要么全部成功,要么都插入失败,否则只插入一个表成功会引起数据库的不一致。很显然,这是一个事务处理(transcation),要么commit成功,要么则rollback。在代码中,利用C#中提供的Transcation类来实现,代码如下:         private void btn_submit_Click(object sender, System.EventArgs e)         {             string strconn = ConfigurationSettings.AppSettings["dsn"];             SqlConnection cnn = new SqlConnection(strconn);             SqlCommand cmd = new SqlCommand();             SqlTransaction transaction = null;             try             {                 cnn.Open();                 // 先插入分店shop表,再插入经理Manager表,并将其作为一个事务进行处理                 transaction = cnn.BeginTransaction();//启动事物                 cmd.Transaction = transaction;                 cmd.Connection = cnn;                 // 插入分店shop表                 string shopstr = "insert into shop values('" + tbx_shopid.Text + "','" + tbx_shopname.Text + "','" + tbx_shopaddress.Text + "','" + tbx_shopphone.Text + "')";                 cmd.CommandType = CommandType.Text;                 cmd.CommandText = shopstr;                 cmd.ExecuteNonQuery();                 // 插入经理Manager表                 string managerstr = "insert into manager values('" + tbx_managerid.Text + "','" + tbx_managerpassword.Text + "','" + tbx_managername.Text + "','" + tbx_shopid.Text + "')";                 cmd.CommandType = CommandType.Text;                 cmd.CommandText = managerstr;                 cmd.ExecuteNonQuery();                 // 提交事务                 transaction.Commit();                 lbl_msg.Text = "添加分店操作成功";             }             catch(Exception ex)             {                 lbl_msg.Text = "添加分店操作失败";                 transaction.Rollback();//发生回滚             }             finally             {                 cnn.Close();             }         }


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