方式一:
String sql="select fi.id, fi.name FROM meeting_fee_item mfi,fee_item fi " + "where fi.id=mfi.feeitemid and mfi.id=" + meetingFeeItemId;
Session session = getSessionFactory().getCurrentSession(); Query query=session.createSQLQuery(sql); List alist= query.list(); List<FeeItem> list = new ArrayList<FeeItem>(); if (alist != null && alist.size() > 0) { for (int i = 0; i < alist.size(); i++) { Object[] objects = (Object[]) alist.get(i); FeeItem feeItem = new FeeItem(); feeItem.setId((Integer) objects[0]); // id必须的 feeItem.setName((String) objects[1]); 相对应的配置所查询的字段,如fi.id,f.name,有多少个,就相应配 System.out.println("object: "+(String) objects[1]); list.add(feeItem); } } return list; }
解决了类型转换异常问题。。
方式二:
回调模式
public Object doInHibernate(Session session) throws HibernateException, SQLException { String sql = "select *,d.roomNo as roomNo from (select a.id,a.name,a.zwu,b.name as unitsName,b.address,b.zip,a.phone,a.mail,a.cellphone from user a,units b where a.unitsId=b.id "; if (unitsTypeId != null && unitsTypeId != 0) { sql += " and b.unitstypeid=" + unitsTypeId; } sql += " ) c left join register d on c.id=d.userid "; SQLQuery q = session.createSQLQuery(sql).addScalar("name", Hibernate.STRING).addScalar("zwu", Hibernate.STRING) .addScalar("unitsName", Hibernate.STRING).addScalar( "address", Hibernate.STRING).addScalar("zip", Hibernate.STRING).addScalar("phone", Hibernate.STRING).addScalar("mail", Hibernate.STRING).addScalar("cellphone", Hibernate.STRING).addScalar("roomNo", Hibernate.STRING);
。。。。
下面进行类型转换,大致如上一。