datagridview某列格式化成两位小数
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datagridView.columns[i]/defaultCellStyle.Format='f";
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Math.Round方法
应该还有math.ceiling和floor double d =12345678.90123;2d.ToString("F2"); //d=12345678.903string s=d.ToString("###,###.00"); //s=12，345，678.90
Math.Round(4.4); //Returns 4.0. Math.Round(4.5); //Returns 4.0. Math.Round(4.6); //Returns 5.0. Math.Round(45.367,2)//Returns 45.37 double d=1.12345; d=double.Parse(d.ToString("0.00")); 这样后,d=1.12
var num = 3.14159; num = Math.round(num * 100) / 100;
C#下如果显示保留小数位数，及百分号的解决方法:
1、用NumberFormatInfo类来解决. System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();
provider.PercentDecimalDigits = 2;//小数点保留几位数. provider.PercentPositivePattern = 2;//百分号出现在何处. double result = (double)1 / 3;//一定要用double类型. Response.Write(result.ToString("P", provider));
2、用toString方法. public string getRate(double hcount, double task) { string rValue; string temp=""; if (task == 0) task = 1; double db = (hcount / task) * 100; if (hcount >= task) rValue = "100%"; else rValue = db.ToString("#0.#0") + "%"; ; return rValue; }
string str1 = String.Format("{0:N1}",56789); //result: 56,789.0string str2 = String.Format("{0:N2}",56789); //result: 56,789.00string str3 = String.Format("{0:N3}",56789); //result: 56,789.000string str8 = String.Format("{0:F1}",56789); //result: 56789.0string str9 = String.Format("{0:F2}",56789); //result: 56789.00string str11 =(56789 / 100.0).ToString("#.##"); //result: 567.89string str12 =(56789 / 100).ToString("#.##"); //result: 567
本文来自博客，转载请标明出处：http://blog.csdn.net/wahaccp/archive/2008/12/01/3419277.aspx
