extjs3.3.1中继承实现代码的抽取和调用

    技术2025-11-26  15

    今天看了一下extjs中继承部分的代码,并把它抽取出来,加了些注释,并写了调用方法。具体如下:

    <script>

    Ext = function() { };Ext.isIE = false;//这里就不去管是不是IE了,不是问题的重点,我是在firefox下调试处理的。Ext.apply = function(o, c, defaults){    // no "this" reference for friendly out of scope calls    if(defaults){        Ext.apply(o, defaults);    }    //extjs在这里做了子类方法对父类方法的覆盖处理    if(o && c && typeof c == 'object'){        for(var p in c){            o[p] = c[p];        }    }    return o;};

    Ext.override=function(origclass, overrides){            if(overrides){                var p = origclass.prototype;                Ext.apply(p, overrides);                if(Ext.isIE && overrides.hasOwnProperty('toString')){                    p.toString = overrides.toString;                }            }        };Ext.extend=function(){            // inline overrides            var io = function(o){                for(var m in o){                    this[m] = o[m];                }            };            var oc = Object.prototype.constructor;

                return function(sb, sp, overrides){               //只有两个参数的情况下,将参数转成三个参数的形式统一处理                if(typeof sp == 'object'){                    overrides = sp;                    sp = sb;                    //如果只有两个参数,将第二个参数的constructor作为subclass                    //这也出现了另人迷惑的问题:传两个参数时,生成类实例时,sp的constructor会执行,                    //而传三个参数时,overrides的constructor不会执行,这也是无奈之举,javascript没有java的overload特性                    //extjs的代码注释也有说明:传三个参数的形式下,第一个参数就是subclass的constructor,第二个是superclass,第三个参数用于copied into the subclass's prototype                    sb = overrides.constructor != oc ? overrides.constructor : function(){sp.apply(this, arguments);};                  }                //造了一个空构造方法的函数,用来接收superclass的prototype                var F = function(){},                    sbp,                    spp = sp.prototype;

                    F.prototype = spp;                //原型继承的关键代码在这里,将subclass的原型指向一个F的实例,用F的实例比直接用superclass的实例好,                //原因在于这样处理创建子类时就不用执行superclass的构造函数,而是执行一个空构造函数F                sbp = sb.prototype = new F();                //修正subclass的prototype的constructor指向                sbp.constructor=sb;                //其实subclass的superclass为superclass的prototype                sb.superclass=spp;                                //父类在创建完后,其constructor都不会是Object的constructor,为什么要修正父类的constructor,这个搞不明白                if(spp.constructor == oc){                    spp.constructor=sp;                }                                sb.override = function(o){                    Ext.override(sb, o);                };                sbp.superclass = sbp.supr = (function(){                    return spp;                });                sbp.override = io;                //这里把overrides的方法拷贝给子类的prototype                Ext.override(sb, overrides);                //给子类添加extend方法,调用时只传overrides参数就可以生成子类的子类                sb.extend = function(o){return Ext.extend(sb, o);};                return sb;            }(); //返回的是匿名方法的执行结果,也就是sb        };        //第一种创建方法,传三个参数创建子类 var Person=function(name){  this.name=name;} Person =Ext.extend(Person,Object,{            getName: function(prefix) {                return this.name;            }});

    var p=new Person("person");console.log("name:"+p.getName());

    //第二种创建方法,传两个参数创建子类var Employee =Ext.extend(Person,{            constructor: function(name, employeeID) {          //  调用父类的方法,这个是参照ext源码写出来的调用方法,感觉不是很爽         Employee.superclass.constructor.apply(this,[name]);                this.employeeID = employeeID;                console.log(employeeID);            },            getEmployeeID: function() {                return this.employeeID;            }        });        var ee=new Employee("employee",11); console.log("name:"+ee.getName()+",id:"+ee.getEmployeeID());

    //第三种创建方法,调父类的extend方法创建子类var Employer =Person.extend({      constructor: function(name, employerID) {                Employer.superclass.constructor.apply(this,[name]);                this.employerID = employerID;                console.log(employerID);            },            getEmployerID: function() {                return this.employerID;            }        });var er=new Employer("employer",12); console.log("name:"+er.getName()+",id:"+er.getEmployerID());</script> 

     

    javascript的继承实现可以参考:

    1.《悟透javascript》

    2.帖子: [原创]JavaScript继承详解

    3.还有一本书《Object-Oriented Javascript》(我是还没来得及看,有空再看)

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