.net中的 delegate的标准C++模拟

    技术2022-05-11  59

    发信人: RoachCock (穷鬼), 信区: Programming 标  题: .net中的 delegate的标准C++模拟 发信站: BBS 水木清华站 (Mon Mar 18 21:11:30 2002) 

    用模板的偏特化和成员模板,重载函数调用运算符成功的实现了delegate,既可以绑定普通函数,也可以绑定对象及其成员函数在cygnuwin下编译通过, 还不支持一个delegate包含多个函数的用法,不过相信很简单,从std::list派生一个类 就可以了   我用的cygun有些毛病, my_delegate d2=my_delegate(t,&Test::f);                            ^如果写成&t,就会导致编译器内部错误,没办法了   我本来写程序是加空行的,贴到BBS上就没了,忍受一下吧 Win32下的各种调用约定很讨厌,没有考虑,不过实现起来不费什么脑筋,就是麻烦, 不管了   // Test.cpp : Defines the entry point for the console application. // #include <stddef.h> template<class T>

    //函数traits,用来提取函数的返回类型

    struct function_traits { }; template<class RT> struct function_traits< RT(*)() > {  typedef RT result_type; }; template<class RT,class AT> struct function_traits< RT(*)(AT) > {  typedef RT result_type;  typedef AT argument_type; }; template<class RT,class AT1,class AT2> struct function_traits< RT(*)(AT1,AT2) > {  typedef RT result_type;  typedef AT1 first_argument_type;  typedef AT2 second_argument_type; };

    // 函数traits,用来提取类成员函数的返回类型

    template<class RT, class OT> struct function_traits< RT (OT::*)() > {  typedef OT object_type;  typedef RT result_type; }; template<class RT, class OT, class AT> struct function_traits< RT (OT::*)(AT) > {  typedef OT object_type;  typedef RT result_type;  typedef AT argument_type;    typedef AT first_argument_type; }; template<class RT,class OT,class AT1,class AT2> struct function_traits< RT (OT::*)(AT1,AT2) > {  typedef OT object_type;  typedef RT result_type;  typedef AT1 first_argument_type;  typedef AT2 second_argument_type; };

    // 把一个普通函数类向转化为类型兼容的指定类的成员函数类型 template <typename OT, typename PFT> struct to_member_function_pointer { }; template <typename OT,typename RT> struct to_member_function_pointer< OT, RT(*)() > {  typedef RT (OT::*type)(); }; template <typename OT, typename RT, typename AT> struct to_member_function_pointer< OT, RT(*)(AT) > {  typedef RT (OT::*type)(AT); }; template <typename OT, typename RT, typename AT1, typename AT2> struct to_member_function_pointer< OT, RT(*)(AT1,AT2) > {  typedef RT (OT::*type)(AT1,AT2); }; template <typename OT, typename RT, typename AT1, typename AT2, typename AT3> struct to_member_function_pointer< OT, RT(*)(AT1,AT2,AT3) > {  typedef RT (OT::*type)(AT1,AT2,AT3); };

    // 转化为const 成员函数

    template <typename OT, typename PFT> struct to_const_member_function_pointer { }; template <typename OT, typename RT> struct to_const_member_function_pointer< OT, RT(*)() > {  typedef RT (OT::*type)() const; }; template <typename OT, typename RT, typename AT> struct to_const_member_function_pointer< OT, RT(*)(AT) > {  typedef RT (OT::*type)(AT) const; }; template <typename OT, typename RT, typename AT1, typename AT2> struct to_const_member_function_pointer< OT, RT(*)(AT1,AT2) > {  typedef RT (OT::*type)(AT1,AT2) const; }; template <typename OT, typename RT, typename AT1, typename AT2, typename AT3> struct to_const_member_function_pointer< OT, RT(*)(AT1,AT2,AT3) > {  typedef RT (OT::*type)(AT1,AT2,AT3) const; };

    // delegate的实现

    template <typename PFT> class delegate {  class object  {  }*m_pObject; // 对象指针,是一个代理对象 typedef typename to_member_function_pointer<object, PFT>::type object_member_fuunction_pointer;  union  {   PFT m_pf;   object_member_function_pointer m_pmf;  }; // 函数指针和成员函数指针的联合体 public:   typedef typename function_traits<PFT>::result_type result_type;     delegate()   {    m_pObject=NULL;    m_pf=NULL;   }     delegate(PFT pf)   {    operator=(pf);   }     template<typename OT>    delegate(    OT *pObject,    typename to_member_function_pointer<OT, PFT>::type pmf    )   {    m_pObject=reinterpret_cast<object*>(pObject);    m_pmf=*(reinterpret_cast<object_member_function_pointer*>(&pmf));   }     template<typename OT>    delegate(    OT &pObject,    typename to_member_function_pointer<OT, PFT>::type pmf    )   {    m_pObject=reinterpret_cast<object*>(&pObject);    m_pmf=*(reinterpret_cast<object_member_function_pointer*>(&pmf));   }     template<typename OT>    delegate(    const OT *pObject,    typename to_const_member_function_pointer<OT, PFT>::type pmf    )   {    m_pObject=const_cast<object*>(reinterpret_cast<object*>(pObject));    m_pmf=*(reinterpret_cast<object_member_function_pointer*>(&pmf));   }     template<typename OT>    delegate(    const OT &pObject,    typename to_const_member_function_pointer<OT, PFT>::type pmf    )   {    m_pObject=const_cast<object*>(reinterpret_cast<object*>(&pObject));    m_pmf=*(reinterpret_cast<object_member_function_pointer*>(&pmf));   }     delegate & operator=(PFT pf)   {    m_pf=pf;    m_pObject=0;    return *this;   }   template<int> :gcc的函数模板不许无参数,加了个占位的"int"才能通过    result_type operator()()   {    if(m_pObject)     return (m_pObject->*m_pmf)();    else     return m_pf();   }   template<typename AT>    result_type operator()(    AT a1    )   {    if(m_pObject)     return (m_pObject->*m_pmf)(a1);    else     return m_pf(a1);   }   template<typename AT1, typename AT2>    result_type operator()(    AT1 a1,    AT2 a2    )   {    if(m_pObject)     return (m_pObject->*m_pmf)(a1,a2);    else     return m_pf(a1,a2);   }   template<typename AT1, typename AT2, typename AT3>    result_type operator()(    AT1 a1,    AT2 a2,    AT3 a3    )   {    if(m_pObject)     return (m_pObject->*m_pmf)(a1,a2,a3);    else     return m_pf(a1,a2,a3);   } }; int gf(int) {  return 0; } class Test { public:  int f(int){return 0;} }; typedef delegate < int (*)(int) > my_delegate; int main() {  Test t;

     my_delegate d1=&gf; // 普通函数 my_delegate d2=my_delegate(t,&Test::f); //对象和类成员函数 d1(0); //调用 d2(2); }   -- 要钱没有,要命也没有 


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