C#中实现VB.NET中IsNumeric函数！！

方案二：正则表达式(推荐)a)using System;using System.Text.RegularExpressions;

public bool IsNumber(String strNumber){Regex objNotNumberPattern=new Regex("[^0-9.-]");Regex objTwoDotPattern=new Regex("[0-9]*[.][0-9]*[.][0-9]*");Regex objTwoMinusPattern=new Regex("[0-9]*[-][0-9]*[-][0-9]*");String strValidRealPattern="^([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]+$";String strValidIntegerPattern="^([-]|[0-9])[0-9]*$";Regex objNumberPattern =new Regex("(" + strValidRealPattern +")|(" + strValidIntegerPattern + ")");

return !objNotNumberPattern.IsMatch(strNumber) &&!objTwoDotPattern.IsMatch(strNumber) &&!objTwoMinusPattern.IsMatch(strNumber) &&objNumberPattern.IsMatch(strNumber);}

b)public static bool IsNumeric(string value){return Regex.IsMatch(value, @"^[+-]?/d*[.]?/d*$");}public static bool IsInt(string value){return Regex.IsMatch(value, @"^[+-]?/d*$");}public static bool IsUnsign(string value){return Regex.IsMatch(value, @"^/d*[.]?/d*$");}