价格上涨下降

    技术2022-05-11  16

    表 AID  NAME  PRICE    DATE1  aaa    500    2009-01-022  aaa    550    2009-02-023  aaa    480    2009-02-054  bbb    800    2008-12-015  bbb    860    2009-02-016  ccc    900    2009-02-057  ddd    1200    2009-01-018  ddd    1500    2009-03-08 想实现1.取每个类别的Name的最新的日期的记录2. 取每个类别Name 的临近的上期记录 进行比较。 当前的记录跟上期记录的价格 是升了还是降了结果如下:NAME  PRICE    DATEaaa    480      2009-02-05    下降70bbb    860      2009-02-01    上涨60ccc    900      2009-02-05    无ddd    1500    2009-03-08    上涨300请问如何通过语句实现  谢谢===============================================================================declare @t table(ID int, NAME varchar(10), PRICE int,DATE datetime)insert @t select 1,'aaa',500,'2009-1-2'insert @t select 2,'aaa',550,'2009-2-2'insert @t select 3,'aaa',480,'2009-2-5'insert @t select 4,'bbb',800,'2008-12-1'insert @t select 5,'bbb',860,'2009-2-1'insert @t select 6,'ccc',900,'2009-2-5'insert @t select 7,'ddd',1200,'2009-1-1'insert @t select 8,'ddd',1500,'2009-3-8'select a.NAME,a.PRICE,a.DATE,价格变化=case when a.price-b.price<0 then '下降'+ltrim(abs(a.price-b.price)) when a.price-b.price=0 then '无' else '上涨'+ltrim(abs(a.price-b.price)) endfrom     (select * from @t t where id =(select top 1 id from @t where name=t.name order by date desc)) a    join    (select * from @t t where id =(select top 1 id from (select top 2 * from @t where name=t.name order by date desc) t1 where t1.name=t.name order by date)) b     on a.name=b.name


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